Question

http://prntscr.com/52svg0

Answer 1

In the first spinner, there are two odd numbers, out of 4 options (aka \(\frac{2}{4}\)). In the second, there is one vowel, out of three options, \(\frac{1}{3}\)
The chance of both events occurring is \[\frac{2}{4}\times \frac{1}{3}\]

Answer 2

\[\frac{ 2 }{ 12 } Simplify?? \]

Answer 3

\[\frac{ 1 }{ 6 }\] @StudyGurl14

Answer 4

correct