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Find the vertex of the formula f(x)=ax^2+bx+c
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i know the x coordinate is -b/2a but what is the y coordinate?
well you have the line of symmetry, so to find the vertex, substitute this value into the equation f(-b/2a) = a(-b/2a)^2 + b(-b/2a) + c so the vertex is (-b/2a, f(-b/2a)
hmmm aren't you supposed to "complete the square" to get it?
yeah i don't think you can just leave it like that
well... do you know how to "complete the squre" then?
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or do you know what a "perfect square trinomial" is?
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