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Write an equation of a line with slope m = -2/ 5 and passing through the point (5, -2). A. y = -2/5 x - 2 B. y = -2/5 x C. y = -2/5 x + 2 D. y = -2/5 x + 4
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so you want to use this equation \[y=m(x-x)+y\]
or better \[y=m(x-x_{1})+y_{1}\]
you have m and \[x_{1}=5\] \[y-{1}=-2\]
*\[y_{1}=-2\]
y=mx+b
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\[y=\frac{-2}{5}(x-5)-2\] can you do it from here?
so y=-2/5x but idk the rest. im kinda confused @Kkutie7
Ok so use the equation I gave you and multiply through here look \[y=\frac{-2}{5}x+\frac{10}{5}-2\] \[y=\frac{-2}{5}x+2-2\] so its just basically the slope.
so y= -2/5x+2-2 is the answer?
yes and no =) you can 2-2=0 so its just y=-2/5x
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