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Solve log4x + log4(x-2)= log4 15 Help please!
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use basic property of logarithms\[\log_{b} a+\log_{b} c=\log_{b} (ac)\]
now can u use this on your problem?
\[\log_{4} x+\log_{4} (x-2)=\log_{4} 15\] that is given right?
here first two terms on the left hand side has a commom base of 4 ,so we can use the above property \[\log_{4} x(x-2)=\log_{4} 15\] ok?
Is the answer x= -3 or 5 ?
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answer is 5 because it will satisfy the equation
\[x(x-2)=15\\if~X=5~u'\ll~have\\x(x-2)=5(5-2)=15\]
ok got it?
Yeah. I didn't check them at the end. Thanks
yes u have to check because when u'll get 2 answers 1 will not satisfy the main equation and i will satisfy
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