Question

if f(x)=sqrt 36-x^2 then the range of value of f is given by?

Answer 1

but how? @perl

Answer 2

well you can graph it , thats one way.

also you can reason it like this. sqrt(0) = 0, sqrt(1) = 1 , sqrt(4) = 2 , etc.
and i realize that youre domain is -6 <= x < = 6 , so the range is not to infinity

Answer 3

f(0) = sqrt( 36 -0^2) = sqrt(36) = 6

f(6) = 0
f(-6) = 0

so the range is [ 0 , 6 ]

Answer 4

we have to put values of x?

Answer 5

it helps, or you can graph it

Answer 6

there is no simple way to find the range , unless you want to solve for x in terms of y, and then find the domain

Answer 7

ok ty