Question

Really tough maths desperate need of help

Answer 1

Hi been trying to solve this question for the past 20 odd minutes

Answer 2

f(X) = 1 (over) x^2-3

Answer 3

I'm suppose to find f(3)

Answer 4

and then f(2+h)

Answer 5

for the first one i got 1 over 6

Answer 6

@SolomonZelman

Answer 7

\(\LARGE\color{black}{ f(x)=\frac{1}{x^2-3}}\)

To find f(2), \(\Large\color{black}{ f(2)=\frac{1}{(2)^2-3}=\frac{1}{4-3}=1/1=1}\)

Answer 8

Find f(3) the same way, plug in 3 for x.

Answer 9

i did f(3)= 1 over 3^2-3= 1 over 9-3= 1 over 6?

Answer 10

can you see where i went wrong @SolomonZelman ?

Answer 11

Right, it is \(\LARGE\color{black}{ \frac{1}{6} }\)

Answer 12

ok great :) what about the next part (this part im really confused about) f(2+h) thanks again for your help @SolomonZelman