Physics - Medal+Fan
A bowling ball is dropped from the top of a tower and takes 5.6 seconds to hit the ground. What is the displacement?

Question

campbell_st · Answer

isn't displacement 

$$s = ut + \frac{1}{2} at^2$$

u = initial velocity  so u = 0    t = time and a is the acceleration, in this case due to gravity... so you should have a number for that

and t = 5.6 

just substitute and calculate

anonymous · Answer

I am new and trying to learn this how do I substitute and calculate

campbell_st · Answer

well 

$$s = 0 \times 5.6 + \frac{1}{2} \times a \times 5.6^2$$

you need to substitute your value for a... acceleration due to gravity