Question

Physics - Medal+Fan
A bowling ball is dropped from the top of a tower and takes 5.6 seconds to hit the ground. What is the displacement?

Answer 1

isn't displacement

\[s = ut + \frac{1}{2} at^2\]

u = initial velocity so u = 0 t = time and a is the acceleration, in this case due to gravity... so you should have a number for that

and t = 5.6

just substitute and calculate

Answer 2

I am new and trying to learn this how do I substitute and calculate

Answer 3

well

\[s = 0 \times 5.6 + \frac{1}{2} \times a \times 5.6^2\]

you need to substitute your value for a... acceleration due to gravity