Question

help finding x-intercepts!

Answer 1

If im given 12x^2+9x+15=0

Answer 2

\(\large\color{black}{ 12x^2+9x+15=0 }\)

\(\large\color{black}{ 3(x^2+3x+5)=0 }\)

\(\large\color{black}{ x^2+3x+5=0 }\)

\(\large\color{black}{ x^2+3x=-5 }\)

\(\large\color{black}{ x^2+3x+1.5^2=-5+1.5^2 }\)

\(\large\color{black}{ x^2+3x+2.25=-5+2.25 }\)

Answer 3

So only imaginary values can be x-intercepts.

Answer 4

in order to find x intercept ,u just put y =0 in the above given equation and isolate the x and get the x intercept

now do that first and show me your work

Answer 5

@SolomonZelman i think you messed up in the first line

Answer 6

ins;t it supposed to be 3(4x^2+3x+5)

Answer 7

as u have seen on the equation that the value of y has already not given so
just isolate the x
for isolation of x use either the quadratic formula or factorizing method

Answer 8

I did mess up, apologize

Answer 9

ok so using the quadratic equation i've gotten so far until \[-9+\sqrt{-639}/24\]

Answer 10

but 4x^2 will make the b lower, and thus it will certainly have only imaginaries.

Answer 11

12x^2+9x+15=0
take common ''3'' from the above equation
3( 4x^2 +3x+5 ) =0
now use the cross multiplication then u would get this
4x^2 +3x+5 =0
now use here quadratic formula and get the x ...
i hope u got it very well