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y=x-4/x^2-16 what are the asymptotes ?
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factor and cancel first
if you factor its y=1/x-4
no
when you cancel the \(x-4\) you get \[\frac{1}{x+4}\]
which of the following is not an asymptote x = 4 x = -4 y = 0 Both x = 4 and y = 0 All of these are asymptotes.
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??????
one you get \(\frac{1}{x+4}\) find the asymptote by setting \(x+4=0\) and solve for \(x\) (in your head)
x=-4
you get \(x=-4\) IS an asymptote, the others are not
so x=4 and the rest wouldn't be asymptotes only x=-4?
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