Question

Solve each of these systems using the substitution method.
2x + 3y = -4
x − 2y = 5
Answer

x = 1, y = -2

x = -1, y = 2

x = 1, y = 2

x = -2, y = -1

Question 2

2x − y = -2
3y = 6 − 5x
Answer

x = 0, y = 2

x = 2, y = 0

x = 2, y = 2

x = 0, y = -2

Question 3

2x − y = 4
6x − 3y = 7
Answer

y = 2x - 4

No solution

x = 2, y = -4

x = 2, y = 5/3

Question 4

2x − y = 3
4x = 6 + 2y
Answer

Infinitely many solutions

x = 2, y = 1

y = 2x - 3

x = 4, y = 5

Answer 1

Someone pleaseeeeeee help me im stuck i dont understand it just please answer my questions :'[

Answer 2

You could use the method of elimination on these, because you're already given the numbers. Just substitute the numbers that they give you in the answers into the equations in the question.

I've done some of them out, and it looks like both equations in the question have the same answer for x and y