A family of nine has a tradition of drawing two names from a hat to see whom they will each buy presents for. If there are three sisters in the family, and the youngest sister is always allowed the first draw, determine the probability that the youngest sister will draw both of the other two sisters’ names. If she draws her own name, she replaces it and draws another.
There are nine names in the hat, but if she draws her own, she draws again, so for all intents and purposes, there are eight names. The odds of her drawing any one of her sisters on first draw is 2:8, or 1:4. The odds of her drawing the remaining sister's name is 1:7. The odds of drawing these in succession are (1/4)(1/7) = 1/28, or 1:28.
oh okay, i get it, Thanks
ur welcome :)
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