Question

Determine the value of X for which line c is parallel to line d. Then find M<1 and m<2.

#1) m<1 = 100 -x, m<2 = 40 + 2x

#2) m<1 = 90 -6x, m<2 = 100 -8x

Answer 1

Help please: @MAli13chineta

Answer 2

@KamiBug ???

Answer 3

Do you know someone who might??

Answer 4

@johnweldon1993 Do you know how to do this?

Answer 5

:) thanks Kami.

Answer 6

@Batgirl1221Robin do you have any idea?

Answer 7

:) me too

Answer 8

100 - X + 40 + 2x = 180
140 + x = 180
X = 180

Is that right????

Answer 9

100 - X = m<1 ---> 100 - 40 = 60 ---> m<1 = 60

40 + 2x = m<2 ---> 40 + 2(40) = ----> 40 + 80 = 120 ---> m<2 = 120

Am i doing this right???

Answer 10

Anybody feel like answering, please?

Answer 11

Hmm...

if we write all the angles we have for 1 line...we have

Answer 12

so verticle angles are the same so they will have the same angle. Meaning I should set it up to be 100 - x = 40 + 2x?

Answer 13

What do we know about this?



so yes set them equal to each other

\[\large 100 - x = 40 + 2x\]

Answer 14

so X = 20.

Answer 15

which I then plug into 100 - X(20) = m<1
And 40 + 2x(20)?

Answer 16

Indeed (as long as you mean replace 'x' with that) then yes

so m<1 = ? and m<2 = ?

Answer 17

80 and 80?

Answer 18

Correct :)

Answer 19

Do the same to the second equation as well?

Answer 20

uh...I got -111 and - 60......

Answer 21

?

Answer 22

Show me your process :)

Answer 23

90 - 6(20) = 90 - 120 = -30 (type wrong last time.)
and
100 - 8(20) = 100 - 160 = -6

Answer 24

sorry: - 60

Answer 25

Wait no...you wouldnt use the 20 again...you have to go through the whole process again with these new angles.....set them equal to each other first and solve for 'x'

Answer 26

how do I set that up?

Answer 27

Same as before

\[\large 90 - 6x = 100 - 8x\]

solve for 'x'

Answer 28

And I would put 80 for X? I'm afraid I'm a little lost...

Answer 29

never mind. Urgh, sorry.

Answer 30

Alright take a step back....wait do you got it?

Answer 31

X = 5

90 - 6x = 100 -8x
2x = 10
X = 5

Answer 32

So the first time we did

\[\large 100 - x = 40 + 2x\]

we solved for 'x' and found it to be 20

and used that 20 to find the angles in that case...

now we have

\[\large 90 - 6x = 100 - 8x\]

so solve for 'x' again

and yes 5...so then what are the angles?

Answer 33

just a sec, I;m working it out. :)

Answer 34

90 - 6(5) = 90 -30 = 60
and
100 - 8(5) = 100 - 40 = 60

Answer 35

Perfect :)

Answer 36

THANK YOU!! My Geometry class is very loud so it's hard to understand the teacher sometimes. :)

Answer 37

Lol I did terrible in geometry...but now I'm in calc 4 and having a blast lol...and anytime :)

Answer 38

:D Thanks. I may end up asking for your help again int he oming weeks. My class is suppose to get harder: let's do the math: Loud class + fast teacher = lack of understanding.

Answer 39

Lol = come to me ^_^

Answer 40

Thanks! :) One more question?

Answer 41

A classmate said that line AB is parallel to line DC based on the diagram (below), Explain what your classmate did wrong.

Answer 42

I'm not sure, someone tried to explain it but the explanation was long and confusing to me.