can someone help me put f(x)=2(x-3)^2+11 in standard form?

Question

anonymous · Answer

First expand (x-3)^2 what will the equation look like?

anonymous · Answer

honestly i have no idea, can you help me understand it please? @nelsonjedi

anonymous · Answer

(x-3)^2 = (x-3) x (x-3) = what?

anonymous · Answer

seems like its an easy problem but im still so confused. @nelsonjedi

anonymous · Answer

Multiply (x-3) and (x-3)....  x times x = ? , 
                                           x times -3 = ?,  
                                          -3 times x= ?, 
                                          -3 times -3 = ?

anonymous · Answer

x2-6x+9 @nelsonjedi

anonymous · Answer

Very good now substitute that back into the problem for (x-3)^2 what do you have?

anonymous · Answer

f(x)=x2-6x+9+11 ? sorry if it's not right. @nelsonjedi

anonymous · Answer

Never say your sorry for trying  you are close but go back and look at the original equation..what was in front of *x-3)^2  ??

anonymous · Answer

f(x)= 2x^2-6x+9+11
but then you add 9 and 11 right? so
f(x)= 2x^2-6x+20 @nelsonjedi

anonymous · Answer

Close but it is 2(x^2-6x+9)+11  so everything in the parenthesis must be multiplied by 2.

anonymous · Answer

2x^2-12x+18+11
so 
2x^2-12x+29 @nelsonjedi

anonymous · Answer

Good job

anonymous · Answer

thank you so much! (: @nelsonjedi

anonymous · Answer

You are welcome