Question

can someone help me put f(x)=2(x-3)^2+11 in standard form?

Answer 1

First expand (x-3)^2 what will the equation look like?

Answer 2

honestly i have no idea, can you help me understand it please? @nelsonjedi

Answer 3

(x-3)^2 = (x-3) x (x-3) = what?

Answer 4

seems like its an easy problem but im still so confused. @nelsonjedi

Answer 5

Multiply (x-3) and (x-3).... x times x = ? ,
x times -3 = ?,
-3 times x= ?,
-3 times -3 = ?

Answer 6

x2-6x+9 @nelsonjedi

Answer 7

Very good now substitute that back into the problem for (x-3)^2 what do you have?

Answer 8

f(x)=x2-6x+9+11 ? sorry if it's not right. @nelsonjedi

Answer 9

Never say your sorry for trying you are close but go back and look at the original equation..what was in front of *x-3)^2 ??

Answer 10

f(x)= 2x^2-6x+9+11
but then you add 9 and 11 right? so
f(x)= 2x^2-6x+20 @nelsonjedi

Answer 11

Close but it is 2(x^2-6x+9)+11 so everything in the parenthesis must be multiplied by 2.

Answer 12

2x^2-12x+18+11
so
2x^2-12x+29 @nelsonjedi

Answer 13

Good job

Answer 14

thank you so much! (: @nelsonjedi

Answer 15

You are welcome