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Mathematics 31 Online
OpenStudy (anonymous):

https://clackamasweb.owschools.com/media/g_geo_ccss_2014/8/groupi31.gif Find the area of the trapezoid shown. 43.5 sq. units 43.5√3 sq. units

OpenStudy (anonymous):

tan (60) = h/3 \[\sqrt{3} = h/3\] \[3\sqrt{3} = h\] area of trapezoid = \[Area = ((a+b)\div 2 ) h\] a = 10 b =16 h = 3sqrt3

OpenStudy (anonymous):

so which one is it? @sangya21

OpenStudy (anonymous):

neither of these \[\tan 60^0 = \sqrt{3}\] \[h = 3\sqrt{3}\] \[area = ((10+16)/2)* 3\sqrt{3}\] \[area = (26/2)* 3\sqrt{3}\] \[area = 13* 3\sqrt{3}\] \[area = 39\sqrt{3}\]

OpenStudy (anonymous):

its not 39

OpenStudy (anonymous):

thats what my calculation says. let me ask someone for help @StudyGurl14 @Compassionate

OpenStudy (anonymous):

@TheSmartOne

OpenStudy (studygurl14):

What d'ya need help with, friends?

OpenStudy (anonymous):

@StudyGurl14 although we have applied the correct formula, we are not able to get desirable answer. Is there any other way to do this?

OpenStudy (studygurl14):

Hm...It appears you used tan to get the height. Couldn't you have just used the information known about 30-60-90 special right triangles?

OpenStudy (studygurl14):

Although, it probably would result in the same height...let me check.

OpenStudy (studygurl14):

no, the height still comes out to \(\large 3\sqrt{3}\)...

OpenStudy (studygurl14):

Oh, I see what the problem is...yo forgot to add 3 to 16 to find the length of base b

TheSmartOne (thesmartone):

So \[29 \times 3\sqrt{3} \times \frac{ 1 }{ 2 }= Area\]

TheSmartOne (thesmartone):

That is what I am getting so far...

OpenStudy (studygurl14):

Area of trapezoid: \(\large(\frac{b_1+b_2}{2})h\)

TheSmartOne (thesmartone):

Exactly ^^

OpenStudy (anonymous):

Oops.

OpenStudy (studygurl14):

\(\large(\frac{10+(16+3)}{2})(3\sqrt{3})\)

OpenStudy (anonymous):

thanks @StudyGurl14

OpenStudy (studygurl14):

Don't worry @sangya21 , you had the right idea and everything. Just one small mistake that I've made many times over. :)

OpenStudy (studygurl14):

Anytime. :)

OpenStudy (studygurl14):

\(\large(\frac{29}{2})(3\sqrt{3})\rightarrow\frac{29(3)\sqrt{3}}{2}\rightarrow\frac{87\sqrt{3}}{2}\)

TheSmartOne (thesmartone):

and 87/2=43.5

OpenStudy (studygurl14):

\(87\div2=43.5\)

TheSmartOne (thesmartone):

So \[43.5\sqrt{3}\]

TheSmartOne (thesmartone):

Exactly. :)

OpenStudy (studygurl14):

so.... \(\large43.5\sqrt{3}\tt=the~answer\)

OpenStudy (studygurl14):

you keeping beating me to it @TheSmartOne , lol :)

TheSmartOne (thesmartone):

It makes me so happy when my friends get to the answer after me...

TheSmartOne (thesmartone):

No @StudyGurl14 Why are you at 86 SS. Now I have to work harder. :(

TheSmartOne (thesmartone):

When I overtake you in SS I will change my profile pic to whatever yours is then. :)

TheSmartOne (thesmartone):

Once I overtake Cam i will change my profile pic to hers Ok? @camerondoherty And then you are next. :)

OpenStudy (anonymous):

Thank you all:))

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