Question

In a box of candy, there are 7 times as many candies with nuts as candies without nuts. Johnny pulls a candy out of the box at random.

What is the probability that Johnny pulled out a candy without nuts?

Answer 1

Let the number of candies without nuts be n. Then the total number of candies is given by:
n + 7n = 8n
The probability that Johnny pulled out a candy without nuts is therefore:
\[\large P(w/o\ nuts)=\frac{n}{8n}=you\ can\ complete\]

Answer 2

Hint: Divide the numerator and the denominator by n.

Answer 3

@Davidsgirl Are you there?

Answer 4

Im here

Answer 5

If we divide the numerator by n we get:
\[\large \frac{n}{n}=\ ?\]

Answer 6

okay

Answer 7

What do you get if you divide n by n?
\[\large \frac{n}{n}=can\ you\ answer?\]

Answer 8

I got it but thank you