Mathematics
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OpenStudy (anonymous):
Solve the following system of equations:
x - 2y = 14
x + 3y = 9
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OpenStudy (immanuelv):
you could do subtraction
OpenStudy (anonymous):
lel r u srs m9?
x - 2y - 14 = 0
x - 14 = 2y
(x - 14) / 2 = y
x/2 - 7 = y
OpenStudy (anonymous):
x + 3y = 9
x + 3y - 9 = 0
x - 9 = -3y
(x - 9)/-3 = y
x/-3 + 3 = y
OpenStudy (anonymous):
(1, 12)
(-1, -12)
(12, -1)
(12, 1)
OpenStudy (anonymous):
those are the choics
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OpenStudy (anonymous):
(x-2y) - (x+3y) = 14-9
-5y = 5
OpenStudy (anonymous):
The first one is (12, -1)
OpenStudy (anonymous):
what do i do with -5y=5
OpenStudy (anonymous):
???
OpenStudy (anonymous):
wot m8
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OpenStudy (anonymous):
what will be the value of y if -5y =5
OpenStudy (anonymous):
y = -1
OpenStudy (anonymous):
im really lost
OpenStudy (anonymous):
to simplify the equation, work pemdas backwards. Just skip to division for -5y = 5. Now divide both sides by -5. y = -1
OpenStudy (anonymous):
is it -1,-12
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OpenStudy (anonymous):
\[(x-2y) - (x+3y) = 14-9\]
\[-5y = 5\]
y = -1
x - 2y = 14
x - 2(-1) = 14
x + 2 = 14
so x will be?
OpenStudy (anonymous):
The first problem you asked about is (12, -1)
OpenStudy (anonymous):
x=12
OpenStudy (anonymous):
Actually, they're both (12, -1)
OpenStudy (anonymous):
so the answer is (12,-1)
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OpenStudy (anonymous):
Indeed
OpenStudy (anonymous):
correct
OpenStudy (anonymous):
thank you guys
OpenStudy (anonymous):
anytime