The slope of a line is –4 and its y-intercept is (0, 4). What is the equation of the line that is perpendicular to the first line and passes through (–8, 2)?

Question

anonymous · Answer

Do you know the formula for the equation of a straight line given the gradient and a point on said line?

anonymous · Answer

no i don't

anonymous · Answer

Okay so given a point (x1, y1) and a gradient m. The equation is:

(y-y1)=m(x-x1).

Our gradient is -4 and our point is (-8,2). Putting these values in we have:

y-2=4(x+8)

Rearranging this we get: y=4x+34

anonymous · Answer

oh okay that makes sense. Thank you so much for explaining it!!

anonymous · Answer

No problem, happy to help!