What is the equation of the line with an x-intercept of -1 and a y-intercept of 2?
I dont understand how to do it the options are y=2x-2 y=-2x+2 y=2x+2 If someone could show me how its done thatd be great
x-intercept means when y = 0 y-intercept means when x = 0
oh my goodness thank you so much that statement alone just helped me a ton
can you find your 2 points on this line given the intercepts?
so like 0=2(-1)-2, would that be the proper way to solve this?
you have the points find the slope you know the slope is the steepness of the line and it is the same for any 2 points on that line slope,m = change in y /CORRESPONDING change in x for 2 points (x1, y1) and (x2, xy2) the slope is (y2 - y1)/(x2-x1) then with this value for m and any point on the line (x, y) so can write the equation of the line point slope form (y-y1) = m(x-x1) note that you could use (x2, y2) for the equation you pick a point
x/x-intercept+y/y-intercept =1 is the general formula, from herer putting the values of xcintercept and y inercept you wiull get the result
what are your 2 points given the intercepts?
What is the equation of the line with an x-intercept of -1 and a y-intercept of 2?
x/(-1)+y/2=1 implies 2x+2=y is the result
@Jonnyloo
@Jonnyloo do you understand the steps outlined above? do you have any questions?
x-intercept of -1 point (-1, 0) y-intercept of 2 point (0, 2) slope (2 - 0)/ (0--1) = 2/1 = 2 using point (0, 2) (y - 2) = 2(x-0) equation y - 2 = 2 x in the form y = mx + b gives y = 2x +2 = choice 3
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