Algebra
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OpenStudy (anonymous):
3a-4 is less than or equal to 5
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OpenStudy (anonymous):
kk
OpenStudy (anonymous):
again you have to bring -4 to the other side to get 3a alone
OpenStudy (anonymous):
so plus 4 on both sides and nowits 3a is less then or equal to 9
OpenStudy (anonymous):
now get a alone and divide 3 to both sides and it should be a is less then or equal to 3
OpenStudy (anonymous):
if im right
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OpenStudy (anonymous):
can you medal me if im right please
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
what are your answer choices
OpenStudy (anonymous):
i dont have any for this one i have to type the answer
OpenStudy (anonymous):
im pretty sure its the answer
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
medal plas
OpenStudy (anonymous):
any more questions or u good?
OpenStudy (anonymous):
one more
OpenStudy (anonymous):
n/-3+5>4
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OpenStudy (anonymous):
sorry was afk
OpenStudy (anonymous):
is it just n-3 or n/-3
OpenStudy (anonymous):
n over -3
OpenStudy (anonymous):
n/-3
OpenStudy (anonymous):
oooo
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OpenStudy (anonymous):
give me a sec on this one
OpenStudy (anonymous):
first we need to bring 5 to 4
OpenStudy (anonymous):
by - so -n/3 <-1
OpenStudy (anonymous):
and with the fraction you have to flip it so it would be -3/n> -1/1
OpenStudy (anonymous):
what are your choices
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OpenStudy (anonymous):
n>3???
OpenStudy (anonymous):
no choice for this one either
OpenStudy (anonymous):
i would go for n>3 buttt im not 100 percent sure get @iGreen to help
OpenStudy (anonymous):
it should check your answers for you
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OpenStudy (igreen):
\(3a - 4 \le 5\)
Add 4 to both sides:
\(3a \le 9\)
Divide 3 to both sides.
What's 9 / 3? @Trusavvy
OpenStudy (anonymous):
3
OpenStudy (anonymous):
i dont think you wrote it write @iGreen
OpenStudy (anonymous):
n/-3+5>4
OpenStudy (anonymous):
a is les than or equal to 3
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OpenStudy (anonymous):
the 5 and 4 are in the wrong spots cause when you bring the 5 to the 4 it should be -1
OpenStudy (anonymous):
cause you have to -5 on both sides even to the 4 which is gonna make it -1
OpenStudy (anonymous):
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