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The legs of a right triangle are 4 units and 7 units. What is the length of the hypotenuse?
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@iGreen
@iGreen
what is 7+4=?
use the pythogorean theorm
hypotenuse =\[\sqrt{base^2+perpendicular^2}\]
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\[hypotenuse=\sqrt{4^2+7^2}\]
solve it further ..inside root it is 4^2 and 7^2
\(a^2 + b^2 = c^2\) \(4^2 + 7^2 = c^2\) \(16 + 49 = c^2\) \(65 = c^2\) \(c=\sqrt{65}\) Can you square that? @blackops2luvr
8.0622577483
8.0622577483
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oh, the answer is sqrt 65?
Yep.
The leg of a right triangle is 5 units and the hypotenuse is 8 units. What is the length, in units, of the other leg of the triangle?
That's your answer.
iGreen ill open it in a new qeustion for ur medal.
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