Question

OMG CAN SOMEONE HELP ME, NOW???????????????//////// DO YOU GUYS KNOW TRIG?
:( FOR THE THIRD TIME: The expression 3N + 2/ (N-1)(N-2) can be written in the following form:
A/(N-1)-B/(N-2)
Compute A^2 + B ^2

Answer 1

We don't have to help. Keep in mind we might not know it either.

Answer 2

Ok.

Answer 3

I'm going to keep asking until I find someone who knows. :)

Answer 4

\[
\frac{ 3N + 2}{ (N-1)(N-2) } = \frac{A}{N-1} - \frac{B}{N-2} =
\frac{A(N-2)-B(N-1)}{(N-1)(N-2)} = \\
\frac{ 3N + 2}{ (N-1)(N-2) } = \frac{(A-B)N+(B-2A)}{(N-1)(N-2)} \\
A- B = 3 \\
B-2A = 2 \\
\text{Solve for A and B}
\]

Answer 5

hmmm that doesn't look like trig btw

Answer 6

Then what is it? :|

Answer 7

It's not trig, but I am taking trig and that's what my teacher gave as hmw lol

Answer 8

What did you get for A and B?

Answer 9

A - B = 3
-2A + B = 2

Add them and solve for A.
Then sub A in first equation and solve for B.

Answer 10

B = -8
A = 11 ?

Answer 11

hmmm I don't see it coming out.. myself

Answer 12

A = -5
B = -8