Write an equation of a line perpendicular to y = x - 5 in slope-intercept form that passes through the point (2, -7). 1) y= x - 7 2) y= 2x + 2 3) y= -2x - 5 4) y= -2x - 3
Note that the slope of the line y = x - 5 is 1 so we want a line whose slope is -1, and none of the options satisifies that.
so what do i do? @Ahaanomegas
None of the options are correct. Are you sure you copied them correctly? The correct answer should be y = -x - 5.
@Ahaanomegas i left out 1/2
So what is the new question?
it is suppossed to be 1/2x -5
but its the same question and options
Ah. In that case, the desired slope of the line is -2, so the equation is of the form y = -2x + b, where b is a constant. To find b, note that (2, -7) is a point so \[ -7 = -2 \cdot (2) + b. \]Can you finish from here?
yes thank you very much
You're welcome! The "best response" button is another way of saying thank you. :)
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