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Evaluate the limit as x approaches infinity.
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\[\lim_{x \rightarrow -infinity} \frac{ 6 }{ e^x+7 }\]
do you know \(\displaystyle\lim_{x\to-\infty}e^x\) ?
@Zarkon , I am not sure
look at the graph of \(e^x\)
would it be -infinity?
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no...for any real x we have \(e^x>0\) so it can't be \(-\infty\)
|dw:1415328057083:dw| looks something like this
\[ \lim_{x\to-\infty}e^x = 0 \\ \lim_{x\to-\infty}\frac{6}{e^x+7} = \frac{6}{0+7} = \frac 67 \]
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