what is wrong with this question (this is an easy one) "solve \(-ax + 3b > 5\) for \(x\) "
Can I answer?
no
Ok. lol
We shall never answer such filth as inequalities....
So we can't answer.
:P
i dont see any proper punctuation :)
no just not @TheSmartOne because he/she already knows
Its a he. :)
@satellite73 I am sure you already know. I have seen you answer harder questions.
@amistre64 ok wise guy what is wrong with this question? "solve \(-ax+3b>5\) for \(x\)" is that better?
lol
;) better yes. it could use more color, but thats an asthetic and not really a boo-boo.
Subtract 3b on both sides. \[-ax>5-3b\] Divide by -a on both sides. But we do not know if a is positive or negative so we get stuck there. @satellite73
I do not know how to get past that. If anyone can explain it.
subtract 5 and add ax ... then declare for a>0 and a<0 when dividing off the a
Oh.
\[\begin{array}l\color{red}{\normalsize\text{w}}\color{orange}{\normalsize\text{h}}\color{#9c9a2e}{\normalsize\text{a}}\color{green}{\normalsize\text{t}}\color{blue}{\normalsize\text{ }}\color{purple}{\normalsize\text{i}}\color{purple}{\normalsize\text{s}}\color{red}{\normalsize\text{ }}\color{orange}{\normalsize\text{w}}\color{#9c9a2e}{\normalsize\text{r}}\color{green}{\normalsize\text{o}}\color{blue}{\normalsize\text{n}}\color{purple}{\normalsize\text{g}}\color{purple}{\normalsize\text{ }}\color{red}{\normalsize\text{w}}\color{orange}{\normalsize\text{i}}\color{#9c9a2e}{\normalsize\text{t}}\color{green}{\normalsize\text{h}}\color{blue}{\normalsize\text{ }}\color{purple}{\normalsize\text{t}}\color{purple}{\normalsize\text{h}}\color{red}{\normalsize\text{i}}\color{orange}{\normalsize\text{s}}\color{#9c9a2e}{\normalsize\text{ }}\color{green}{\normalsize\text{q}}\color{blue}{\normalsize\text{u}}\color{purple}{\normalsize\text{e}}\color{purple}{\normalsize\text{s}}\color{red}{\normalsize\text{t}}\color{orange}{\normalsize\text{i}}\color{#9c9a2e}{\normalsize\text{o}}\color{green}{\normalsize\text{n}}\color{blue}{\normalsize\text{?}}\color{purple}{\normalsize\text{}}\end{array}\]
The w has to be capital.
Its too colorful it hurts me eyes...
3b - 5 > ax if a < 0 then (3b-5)/a < x if a > 0 then (3b-5)/a > x
you cannot get past it it was written by an idiot who assumes that \(-a\) is negative because of the minus sign thus forever confusing people about what a variable is
Yes. I was right.
lol
@confluxepic yes you are right
http://openstudy.com/study#/updates/545c3c96e4b0c2835b84f367 Well he got his question answered afterall...
Cool.
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