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indefinite integral problem
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\[\int\limits_{?}^{?} (x^2+1) (x^3+3x)^4 dx\]
this is what i have so far u=x^(3)+3x and du/3x^(2)+3=dx
Substitute \(u=x^3+3x\), so that \(du=(3x^2+3)~dx\), i.e. \(\dfrac{1}{3}du=(x^2+1)~dx\). \[\int (x^2+1)(x^3+3x)^4~dx=\frac{1}{3}\int u^4~du\] Yep you've got it.
but i have problem with the plug in part
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