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OpenStudy (anonymous):
Find the exact value of the expression given that secx=3/2, cscy=3 and x and y are in quadrant 1
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OpenStudy (anonymous):
Oh and the expression is sin (x+y)
OpenStudy (anonymous):
you need a bunch of numbers
you need \(\sin(x), \cos(x), \sin(y), \cos(y)\)
do yuou know how to find them ?
OpenStudy (anonymous):
I know how to find the cos x and siny
but not the others
OpenStudy (anonymous):
\[\cos(x)=\frac{2}{3}\]and you need \(\sin(x)\) draw a triangle
OpenStudy (anonymous):
|dw:1415333619389:dw|
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OpenStudy (anonymous):
the third side, by pythagoras , is
\[\sqrt{3^2-2^2}=\sqrt5\]
OpenStudy (anonymous):
OOPS!
\[\huge \sin(x)=\frac{\sqrt5}{3}\] sorry
OpenStudy (anonymous):
Ok that makes sense. And you do that similarly to cosy, right? Is cosy=(2sqrt2)/3
OpenStudy (anonymous):
yes you do
idk i didn't do it but i can check real quick
OpenStudy (anonymous):
yes you are right
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OpenStudy (anonymous):
Ok well if that is right I should be able to do the rest. Thank you so much!
OpenStudy (anonymous):
yw, "addition angle" formula from here on in
plug in the numbers, see what you get
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