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Mathematics 7 Online
OpenStudy (anonymous):

Fan + Medal

OpenStudy (anonymous):

Suppose you have data that shows that 12% of athletes test positive for steroids. You also know that 11% of athletes test positive for steroids and actually use steroids. What is the probability that an athlete uses steroids, given that he tests positive?

OpenStudy (anonymous):

0.37 0.43 0.51 0.67 0.92

OpenStudy (mvpriest6):

0.67 I think

OpenStudy (anonymous):

Can you explain why you think that?

OpenStudy (mvpriest6):

um... Im not quite sure if it is right so I dont want to mess you up

OpenStudy (anonymous):

Oh, can someone else help me out?

OpenStudy (mvpriest6):

let me try to redo it

OpenStudy (anonymous):

I personally thought it was 0.37

OpenStudy (mvpriest6):

why?

OpenStudy (anonymous):

.this is conditional probability P(A|B)=P(AandB)P(B) A is prob he uses steroids B is prob he tests positive A and B is prob he both uses and tests positive

OpenStudy (anonymous):

Because I thought it was 0.25 and 0.37 was the closest

OpenStudy (mvpriest6):

I think your right

OpenStudy (mvpriest6):

yea, your right

OpenStudy (anonymous):

I agree with @I_Need_Help_With_Home

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