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(x-x^2)/(x^2+1)<0 ?
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x=1
it's an inequation
\[x \in(-\infty,1) ?\]
I would find when the top=0 that is when x-x^2=0 x^2+1 never equals 0 so technically we have to just look at x-x^2<0
After solving x-x^2=0 I like to test intervals for which x-x^2 is positive or negative around the zeros I found for x-x^2
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