Solve the given system, using the substitution method.

y = 3x+7
6x-2y = 12

A.There is no solution.
B.(14, 12)
C.(12, 14)
D.There are an infinite number of solutions.

Question

Solve the given system, using the substitution method.

y = 3x+7
6x-2y = 12

A.There is no solution.
B.(14, 12)
C.(12, 14)
D.There are an infinite number of solutions.

anonymous · Answer

Note that $$ 6x - 2y = 6x - 2(3x-7) = 6x - 6x + 14 = 14, $$which cannot be 12, so no solution.

igreen · Answer

Substitute 3x - 7 for y in the second equation:

6x - 2y = 12

6x - 2(3x - 7) = 12

Distribute -2 into the parenthesis:

6x - 6x + 14 = 12

Subtract 6x - 6x, what do you get? @ihateschool99

igreen · Answer

@Ahaanomegas Don't give out answers.

anonymous · Answer

Sorry; at least I showed my work.