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how do i solve this equation? (3(x)^1/2)/2-3/(2(x)^1/2)
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all that equal to 0
ok
(3/2)(\sqrt(X)-3/2(\sqrt(x)\
http://www.slader.com/textbook/9780538497817-stewart-calculus-7th-edition/243/exercises/21/#
if it's equal to zero, it makes it easy add the 2nd term to both sides of the equation \[\frac{3x^{\frac{1}{2}}}{2} = \frac{3}{2x^\frac{1}{2}}\] cross multiply and remember, multiplying the same base, add the powers \[3 \times 2 \times x^{\frac{1}{2} + \frac{1}{2}} = 2 \times 3\] which becomes 6x = 6 hope it helps
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i cant understan step e
i see
makes perfect sense now :D
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