Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

What is the resulting ordered pair if the value of the independent variable is –2? f(x)=2x^3+3^2 If the function f(x)=3/2x-10 were graphed, which of the following would be true? A survey is taken and finds that 4,250 people in town would vote for candidate A. The survey company says their results are accurate within 2%. Write an absolute value inequality with x as the possible survey results. Which of the following equations represents a line that is parallel to the line below? I will post attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

@MGLMystiicz @jinxhead20 @Princer_Jones @Kommander_Kitten @Catlover5925

OpenStudy (anonymous):

@roz_mar23

OpenStudy (anonymous):

(-2,-7) 1st answer. (x,f(x)) is the ordered parir. Here x=-2

OpenStudy (anonymous):

this is confusing.....

OpenStudy (anonymous):

last answer is A. since the slope of the parallel lines are equal. see the points (3,-3) and (0,-4) are on the curve the slope of the line joining these two points is 1/3 hence 1st option is correct

OpenStudy (anonymous):

The first one: f(x)=2x^3+3^2. The independent variable is just the variable in which YOU input the value to make f(x) equal something. They give this as -2. So x is simply -2. Therefore, f(x) is just \[2(-2)^{3}+3^{2}\] Simplify and we get -7. So the ordered pair would be (-2, -7)

OpenStudy (catlover5925):

ok ur formula is Y=Mx +b...B is the y intercept and here it is -4 M is the slope ur slope is a positive 1/3....idk why ur answers have -2 but I would choose A because it has the right slope

OpenStudy (anonymous):

^

OpenStudy (anonymous):

Okayy thank you. Can come one help with number 1 cause -2,-7 aren't answers

OpenStudy (anonymous):

is it 3^2 in the 1st question? You check it// @RosePetal_

OpenStudy (anonymous):

not the choices are (-5,-2) (-2,-4) (-2,-28) (-4,-2)

OpenStudy (anonymous):

I said, 1st question is it given 3^2 in the end??

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

Hello? Please I really need help bad. Im not understanding the first 3 questions

OpenStudy (anonymous):

@AnswerMyQuestions @help?!?!?!

OpenStudy (anonymous):

What are the answer choices for the first question?

OpenStudy (anonymous):

(-5,-2) (-2,-4) (-2,-28) (-4,-2)

OpenStudy (anonymous):

Can you post a screenshot of the equation we're supposed to be solving then? I think you might have copied it wrong

OpenStudy (anonymous):

OpenStudy (anonymous):

That changes things :3

OpenStudy (anonymous):

(-2,-4) 1st answer

OpenStudy (anonymous):

See you posted wrong question in the beginning

OpenStudy (anonymous):

^^

OpenStudy (anonymous):

Also, for the second one, we need to see answer choices for it. The question your asking doesn't make any sense.

OpenStudy (anonymous):

oh i did! opps oh my gawd I'm an ihdiut aha thanxx ill post the answers for the second one rn

OpenStudy (anonymous):

OpenStudy (anonymous):

Those are the answers above for question 2 ^^^

OpenStudy (anonymous):

Answer B. here the first order derivative is greater than 0 hence it is an increasing function.

OpenStudy (anonymous):

@RosePetal_

OpenStudy (anonymous):

Thanxx so much!!!!!

OpenStudy (anonymous):

what about the third one here are the answers

OpenStudy (anonymous):

I think its A

OpenStudy (anonymous):

@RosePetal_ you reasoning?..

OpenStudy (anonymous):

Sorry I meant b

OpenStudy (anonymous):

I dont know its A or B, the question is not clear

OpenStudy (anonymous):

because your taking the 4,250 out of the survey amount and its equal or less than .002 percent accurate

OpenStudy (anonymous):

rhs is clearly 2/100=0.02 oh yes...

OpenStudy (anonymous):

okay thank you so much for your help!!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!