Will give medal/fan/etc. Three cards are dealt from a well-shuffled standard deck. f. Find the probability that either one or two of the
I've worked out part of it, and i know the answer, but I don't know why my answer doesn't match the given answer.
1 Ace = 4/52 * 48/51 * 47/50 * 3 3 because if A = Ace and X= Not ace, the combos for three cards are AXX, XAX, XXA
2 Ace = 4/52 * 3/51 * 48/50 * 3 3 because if A = Ace and X = not ace, the combos for the there cards are AAX, AXA, XAA
Given answer = 48/221
I thought that I had to add them together because "either" means that its mutually exclusive
That will mean that whatever I add to has to add up to 173/221 or 4325/5525
first see if ur question is complete
Well the question has parts a-f, but I finished a-e
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