Given the function f(x) = The quantity of 4x minus 2, divided by 3, which of the below expressions is correct? f−1(x) = The quantity of 2 minus 4x, divided by 3. f−1(x) = The quantity of 3x minus 2, divided by 4. f−1(x) = The quantity of negative 4x minus 2, divided by 3. f−1(x) = The quantity of 3x plus 2, divided by 4.
@jim_thompson5910 @Josh21096
First replace f(x) with y. Then swap x and y. Afterwards, solve for y. \[\Large f(x) = \frac{4x-2}{3}\] \[\Large y = \frac{4x-2}{3}\] \[\Large x = \frac{4y-2}{3}\] \[\Large 3x = 4y-2\] I'll let you finish up.
im so confused dont u divide by 3
@jim_thompson5910
I multiplied both sides by 3 to move the 3 over. I ultimately want to solve for y.
so subtract 4 from both sides
why not add 2 to both sides 3x = 4y - 2 3x+2 = 4y 4y = 3x+2 y = ???
y=3/4+2
so it be D
I think you meant to say \[\Large y = \frac{3x+2}{4}\]
ya i just cant type it out like that
alright, just checking, yes it is D
thank you
you're welcome
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