Given the function f(x) = The quantity of 4x minus 2, divided by 3, which of the below expressions is correct?
f−1(x) = The quantity of 2 minus 4x, divided by 3.
f−1(x) = The quantity of 3x minus 2, divided by 4.
f−1(x) = The quantity of negative 4x minus 2, divided by 3.
f−1(x) = The quantity of 3x plus 2, divided by 4.
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OpenStudy (anonymous):
@jim_thompson5910 @Josh21096
jimthompson5910 (jim_thompson5910):
First replace f(x) with y. Then swap x and y. Afterwards, solve for y.
\[\Large f(x) = \frac{4x-2}{3}\]
\[\Large y = \frac{4x-2}{3}\]
\[\Large x = \frac{4y-2}{3}\]
\[\Large 3x = 4y-2\]
I'll let you finish up.
OpenStudy (anonymous):
im so confused dont u divide by 3
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
I multiplied both sides by 3 to move the 3 over. I ultimately want to solve for y.
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OpenStudy (anonymous):
so subtract 4 from both sides
jimthompson5910 (jim_thompson5910):
why not add 2 to both sides
3x = 4y - 2
3x+2 = 4y
4y = 3x+2
y = ???
OpenStudy (anonymous):
y=3/4+2
OpenStudy (anonymous):
so it be D
jimthompson5910 (jim_thompson5910):
I think you meant to say
\[\Large y = \frac{3x+2}{4}\]
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