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Calculus1 15 Online
OpenStudy (anonymous):

I am weak in mathmatics please any body tell me what is happeing here http://postimg.org/image/r8hkqvcol/

ganeshie8 (ganeshie8):

\[\large \rm y^2 \] is same as : \[\large \rm y^2 +1-1\]

ganeshie8 (ganeshie8):

would you agree ?

OpenStudy (anonymous):

i am confuse in y^2/Y^+1

ganeshie8 (ganeshie8):

\[\large \rm \dfrac{y^2}{y^2+1} \] is same as : \[\large \rm \dfrac{y^2+1-1}{y^2+1} \]

OpenStudy (anonymous):

and also how y^2-(Y^2+1)/y^2+1 come

OpenStudy (anonymous):

y2+1−1y2+1 yes its sam but please tell how what you do in this step

OpenStudy (anonymous):

confuse in this step http://postimg.org/image/4mi041x81/

ganeshie8 (ganeshie8):

that step is confusing to me too, see if below steps make sense :

ganeshie8 (ganeshie8):

\[\large \begin{align}\rm \dfrac{y^2}{y^2+1} &= \dfrac{y^2+1-1}{y^2+1}\\~\\~\\& = \large \rm \dfrac{(y^2+1)-(1)}{y^2+1} \\~\\&= \dfrac{y^2+1}{y^2+1} - \dfrac{1}{y^2+1}\\~\\~\\&=1 - \dfrac{1}{y^2+1}\end{align}\]

OpenStudy (anonymous):

thanks but please tell me what you do in this step http://postimg.org/image/o8nk2fwlb/

ganeshie8 (ganeshie8):

we have this property for splitting/combining fractions : \[\large \rm \dfrac{\heartsuit-\spadesuit }{\text{stuff}} = \dfrac{\heartsuit}{\text{stuff}}- \dfrac{\spadesuit}{\text{stuff}} \]

ganeshie8 (ganeshie8):

you can split fractions like that, the overall value wont change

OpenStudy (anonymous):

thank you :) now i have understood

ganeshie8 (ganeshie8):

good :) you could also use long division for reducing the degree of numerator

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