Question

Positive and Negative Integers Problem!

Answer 1

Not really too sure where to even start on this porblem! Please help!

Answer 2

just counting:
if x =1, then 0 is only one even before it, right?
if x =3, then 0, 2
if x = 5, then 0, 2, 4
if x =7 then 0,2,4,6
........
now compare:
you can see that \(\dfrac{x+1}{2}\) = the number corresponds to x.

Answer 3

is zero considered a positive even integer

Answer 4

if positive is not negative then, zero is positive
but if
by same definition
negative is not positive them, zero is negative,
so zero exists to be positive and negative but this cannot be because positive is not negative. therefore
positive>0
negative<0
hence
x-1
----
2

Answer 5

http://www.mathsisfun.com/numbers/even-odd.html

Answer 6

@dan815

Answer 7

@bszent @Loser66 @dan815 please check the solution

Answer 8

Great!!

Answer 9

just one question: is 1 odd? if it is odd, why does your series starts at 2?

Answer 10

The series starts at 2 because we are asked to find the even numbers less than the given odd number.

Answer 11

@Loser66

Answer 12

*even positive. 1 is not even, so we dont start with 1

Answer 13

Ok, depends on how we define 0, we get the result. :)

Answer 14

No Definition: A number is said to be positive if it is greater than 0. Definition: A number is said to be negative if it is less than 0. Clearly 0 is not greater than 0 or lesser than 0. Hence 0 is neither positive nor negative. @Loser66

Answer 15

ok, you are right :)

Answer 16

Oh okay so it's (x-1)/2?

Answer 17

yes @bszent