Given derivatives how do you find the equation? Problem in comments

Question

anonymous · Answer

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geerky42 · Answer

saying we have $P(x) = ax^2+bx+c$, we have $P'(x)=2ax+b$ and $P''(x)=2a$

we are given that $P''(1)=8$ So that means $2a = 8$

We can find a. You should get $a = 4$.

Then we have $P'(x) = 8x+b$

We are given that $P'(1) = 6$  So you have $P'(1) = 8(1)+b=6$

Solve for b.

See what I did here? Can you solve for c then find $P(x)$ now you have value for $a$, $b$ and $c$?

anonymous · Answer

I figured out what I did wrong. I put p"(x)=8a making a=1 which messed up the rest of the problem. Thank you :)

geerky42 · Answer

Ok, no problem