Please Help!!!! Please Help!!! Solve the system of equations. x + 3y = -1 2x + 2y = 6
Have you attempted to solve this yet?
Not really.
I really need an answer ! Please!
Teach a man to fish... https://www.khanacademy.org/math/algebra/systems-of-eq-and-ineq/fast-systems-of-equations/v/solving-systems-of-equations-by-elimination
The options are -4, 1) (2, -1) (4, -1) (5, -2)
Lol cmon jason
Lol, Sorry man. I hate this stuff.
I have 2 more. xD
y= x-1/3 y= 3 +1x
wait what
2(5) + 2(-2) = 10 + (- 4) = 6 D
why are u giving coordinates
Thanks SuperFly!!!! I have 2 more if your not busy. Its okay if you dont want to.
Solve the following system of equations: x - 2y = 14 x + 3y = 9 (1, 12) (-1, -12) (12, -1) (12, 1)
Ok, just gimme the options too
Anyone up for it?
And Solve the system of equations by substitution. What is the solution for x? 2x + y = 1 4x + 2y = -1 x = 0 x = 2 There is no x value, as there is no solution. x can be any value, as there is an infinite number of solutions.
12 -(-2) = 12 + 2 = 14 C for the first one
Is that for the second one?
Oh Okay the first one
Yeah second one
Okay
Substitution: x + 3y = -1 So then by subtracting 3y... x = -1 - 3y The other equation is 2x + 2y = 6 Substitute 2(-1 - 3y) + 2y = 6 -2 -6y + 2y = 6 -2 -4y =6 -4y = 8 y = 2 Substitute again x + 3(2) = -1 x + 6 = -1 x = - 7 and because (x,y) (-7,2)
^ thanks!!!!
And what about the final one?
And Solve the system of equations by substitution. What is the solution for x? 2x + y = 1 4x + 2y = -1 x = 0 x = 2 There is no x value, as there is no solution. x can be any value, as there is an infinite number of solutions.
Do the same thing, first isolate y in 2x + y = 1, what would that look like?
y=2x +1?
I thinks its C
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