Question

y=x^2-4+6 vertex form

Answer 1

\[y=x^2-4+6\]\[y=x^2+2\]
this is it.

Same thing as,
\[y=(x+0)^2+2\]

Answer 2

so the vertex is (0,2)

Answer 3

and it opens up.

Answer 4

the derivative is a line y=2x
and f''(x) is y=2
and f'''(x) is y=0

sorry for showing offf

Answer 5

just learned the derivatives I am so proud, excuse, understand, and ignore me

Answer 6

Did you mean:
\[y=x*2-4x+6\]