Integral question, seemed easy for me, but I crushed into a big wall.
Please help me. (I'll post the question)

Question

Integral question, seemed easy for me, but I crushed into a big wall.
Please help me. (I'll post the question)

anonymous · Answer

$$\Large \int\limits_{-1}^{1}~e^{u+1}~~du$$I am rewriting it below, to just integrate e^u.$$\Large \int\limits_{-1}^{1}~e(e)^{u}~~du$$The indefinite integral,$$\Large \frac{e(e)^{u+1}}{u+1}$$

And I get an undefined value for the lower sum-:(

anonymous · Answer

The integral of $e^u$ is just $e^u$, not $\dfrac{e^{u+1}}{u+1}$.

anonymous · Answer

The power rule only applies to constant exponents, not variable ones.

anonymous · Answer

ohh damn, I suck so much, tnx

anonymous · Answer

I myself adjusted it to e^u, and then say this bs. Sorry...

anonymous · Answer

I won't do these silly mistakes anymore. I'll pay more attention. Tnx again, S&G

anonymous · Answer

You're welcome!