Question

Find the domain of fg f(x) = x^2 +1 g(x) = 1/X

Answer 1

\(\large\color{black}{ f(x)=x^2+1 }\)

\(\large\color{black}{ g(x)=\frac{\Large{1}}{\Large{x}} }\)


\(\large\color{black}{ f(g(x))=(\frac{\Large{1}}{\Large{x}})^2+1=\frac{\Large{1}}{\Large{x^2}} +1 }\)

Answer 2

this is the g(x).
You know that the denominator can't equal zero, so thus x can't equal zero.
Any other number works for the domain.....