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Mathematics 23 Online
OpenStudy (anonymous):

Help pretty please:) The length of a rectangle is 3 inches more than twice its width, and its area is 65 square inches. What is the width? 2.5 in. 5 in. 6.5 in.

OpenStudy (anonymous):

So we don't know the length and we don't know the width, but we know the width in terms of the length, and we know the area

OpenStudy (anonymous):

sorry, i mean we know the length in terms of the width*

OpenStudy (anonymous):

$$A = lw$$ we know the area, and now the length. $$65 = lw \\ 65 = (3 + 2w)w$$

OpenStudy (anonymous):

then we just solve by distributing then making a factorable quadratic $$65 = 2w^2 + 3w \\ 2w^2 + 3w - 65 = 0$$

OpenStudy (anonymous):

thank you @absurdism

OpenStudy (anonymous):

now just solve that using the quadratic equation

OpenStudy (anonymous):

the positive answer is your width

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