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Convert the polar equation to rectangular equation r=1/(1+sin theta) my answer is y^2(x+1)=r or (y^2(x+1))^2=x^2+y^2 I need somebody to check it for me :D
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@Kainui yes you are here help plz
did you cross multipl
nop
actually lets use the conversion factors x = r cos t y = r sin t x^2 + y^2 = r^2 so we have y/r = sin t
want me to draw how i got the answer?
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r = 1 / ( 1 + y/r ) now cross multiply
r ( 1 + y/r) = 1 r*1 + r* (y/r) = 1 r + y = 1 r = 1 - y now square both sides
r^2 = ( 1 - y ) ^2 x^2 + y^2 = ( 1 - y)^2
what did you get?
let me draw it
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