Mathematics
7 Online
OpenStudy (romantic_ch3micals):
H3LP! 1LL G1V3 4 M3D4L
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OpenStudy (romantic_ch3micals):
13. Which expression is equivalent to 3c(1/3d-9)-7(c+1)+d(c+4)
A)2cd-34c+4d-7
B)2cd-7c-4
C)2cd+34c+4d+7
D)2cd+8c+4
3XPL41N TOO PL34S3
OpenStudy (wmj259):
Multiply the 3c into the parenthesis. and multiply the 7 into the parenthesis. Multiply the d into the parenthesis.
OpenStudy (wmj259):
Can you draw your original question out?
OpenStudy (romantic_ch3micals):
im looking for it
OpenStudy (wmj259):
\[3c \left( \frac{ 1 }{ 3 }d-9 \right)-7\left( c+1 \right)+d \left( c+4 \right)\]
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OpenStudy (wmj259):
Is that correct?
OpenStudy (romantic_ch3micals):
yea
OpenStudy (wmj259):
is the first parentheses correct?
OpenStudy (wmj259):
the d might be misplaced
OpenStudy (romantic_ch3micals):
no, its right
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OpenStudy (wmj259):
okay. So use the distributive property
OpenStudy (wmj259):
To eliminate the parentheses.
OpenStudy (wmj259):
Yes?
OpenStudy (wmj259):
\[\frac{ 3c }{ 3d }-27c-7c-7+cd+4d\]
Simplify
OpenStudy (wmj259):
oops, I meant to say 3/3 dc
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OpenStudy (romantic_ch3micals):
.....im trying to solve it out....curse this problem
OpenStudy (wmj259):
add like terms.
OpenStudy (wmj259):
Look at my picture, take a deep breath and continue.
OpenStudy (romantic_ch3micals):
*bangs head on table*
OpenStudy (wmj259):
*No need to do that*
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OpenStudy (romantic_ch3micals):
Im going for B...is it right? *drumroll*
OpenStudy (wmj259):
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