Question

Partial fractions help. Question attached below. Will give medal.

Answer 1

So I'm having some trouble splitting this into partial fractions. So far, I have
\[13 = (Ax+B)(x ^{2}+1) + C(2x+3)\]

Answer 2

I think I've seen my error now.

Answer 3

I think you have it set up in a mix and match kinda way if that makes sense.

Answer 4

ooops nvm
you found it

Answer 5

\[\frac{13}{(2x+3)(x^2+1)}=\frac{Ax+B}{x^2+1}+\frac{C}{2x+3}\]
Like the quadratic part should be multiply by that constant and
the linear should be multiply by the other linear.

Answer 6

Is that the error you found?

Answer 7

Hmm, no..i thought that I was supposed to write Bx+c instead of Ax+B, but now I realized that wasn't an error

Answer 8

13=(Ax+B)(2x+3)+C(x^2+1)

Answer 9

Thanks for making it clear :)