Partial fractions help. Question attached below. Will give medal.

Question

itiaax · Answer

So I'm having some trouble splitting this into partial fractions. So far, I have
$$13 = (Ax+B)(x ^{2}+1) + C(2x+3)$$

itiaax · Answer

I think I've seen my error now.

freckles · Answer

I think you have it set up in a mix and match kinda way if that makes sense.

freckles · Answer

ooops nvm
you found it

freckles · Answer

$$\frac{13}{(2x+3)(x^2+1)}=\frac{Ax+B}{x^2+1}+\frac{C}{2x+3}$$
Like the quadratic part should be multiply by that constant and
the linear should be multiply by the other linear.

freckles · Answer

Is that the error you found?

itiaax · Answer

Hmm, no..i thought that I was supposed to write Bx+c instead of Ax+B, but now I realized that wasn't an error

freckles · Answer

13=(Ax+B)(2x+3)+C(x^2+1)

itiaax · Answer

Thanks for making it clear :)