a 55 kg baseball player slides into third base with an initial speed of 4.6 m/s If the coefficient of kinetic friction between the player and the ground is 0.46, what is the player's acceleration?

Question

anonymous · Answer

So first you should really draw a free body diagram, but this website isn't letting me
So we will move onto using Newton's Laws
$$F=m*a$$
in the vertical direction
$$N-m*g=0$$
so
$$N=m*g$$
in the horizontal direction
$$-u*N=m*a$$
so
$$a=-u*N/(m)$$
so
$$a=-u*(m*g)/m=-u*g$$
It seems that a lot of excess information in this problem but it doesn't actually look that bad

anonymous · Answer

Alright so after plugging all that in should I have gotten something like 
$$a=-4.508  m/s ^{2}$$

anonymous · Answer

Yep, that seems reasonable

anonymous · Answer

Alright thank you so much! Life saver! Now I can do the rest of this work. thanks again!

anonymous · Answer

Sure thing man, good luck!