Question

Calculus. Suppose f(2)=3, g(2)=5, f'(2)=-2, g'(2)=4, and f'(5)=11
If h(x)= f(x)g(x), find h'(2)

Answer 1

I'm only confused as to why there is two f'

Answer 2

\[\ h(x) = f(x)g(x)\]\[h'(x) =f'(x) g(x) +g'(x)f(x)\]\[\ h'(2) = f'(2)g(2) + g'(2)f(2)\]

Answer 3

Hm.... Im not sure why there are 2 f's

Answer 4

that would correlate to h'(5) or something maybe?

Answer 5

Maybe to confuse you ~.~ But you get how to solve it from there, right? :)

Answer 6

Yeah I get it from here. Thank you :)

Answer 7

No problem :)