Question

-3sin(theta)+3=2cos^2(theta)

Answer 1

well replace cos^2(theta) with 1-sin^2(theta)

and you get a quadratic equation

\[-3\sin(\theta) + 3 = 2(1 - \sin^2(\theta))\]

or

\[2\sin^2(\theta) - 3\sin(\theta) + 1 = 0\]

this factors to

\[(2\sin(\theta) - 1)(\sin(\theta) -1) = 0\]

now you can solve the equation

Answer 2

hope it helps