The formula s=2n to the square root of L S is the time in seconds to swing back and forth and L is the length of the pendulum in feet A. How long does it take for a three foot pendulum to swing back and forth B. Solve for the formula of L FInd the length of a pendulum that makes one swing in 2.5 seconds
Can you say those variables in a list. Im confused. Like x= a= b=
But I can help you.
S= Seconds L= Length of the pedulum
and the formula is S=2n*sqrt(L) Correct?
You know it's a hard one when a Human Calculator asks O_O
Ahahahaha @Aamirgsen
are little s and big S the same?
|dw:1415833416267:dw| Yes?
yes
And the first question says a swing forward and back is "1" swing or 2 swings?
What is n?
the weight?
I meant pi but isnt a. 10.877
okay so the formula is \[T=2*\pi*\sqrt{\frac{ L }{ G }}\]
so L is the length in feet G is gravity = 9.8 m/s^2 T is the seconds
We wouldnt multiply it by the square root would we??
|dw:1415833637862:dw|
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