Find three consecutive integers such that the sum of twice the smallest and 3 times the largest is 126
Ok lets describe and label the consecutive integers so x is the smalles X+1 is the seconds consecutive integer and the third one, the largest is X+1+1=x+2
Two times the smallest Number +3 Times the largest integer =126 Using the information i have provided above solve for x
i still dont get it, its too hard
do you know what consecutive integers mean?
yea
It means one number after the other so for example three consecutive integers are 3,4,5 or 5,6,7 So we wanna find 3 consecutive integers that when multiply the smallest number and add it to 3 times the largest number the sum will be 126 2 X Smallest Integer + 3 X Largest Integer =126 so the smallest integer is x. That x just represent any integer x+1 is the next integer and x+1+1=x+2 is the largest of the consecutive integers Therefore we have an equation of the following 2(x)+3(x+2)=126 Now solve for x
i got 24 n thankss i understand it alot more
ok x=24 Meaning that the smallest integer is 24 therefore the 3 consecutive integers are 24,25,26
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