Question

1/a^2-1/a=6

Answer 1

\[\huge \frac{1}{a^2}-\frac{1}{a}=6\]?

Answer 2

yes
how do you solve that

Answer 3

you could multiply both sides by \(a^2\) as a good first step
either that, or you have to do the subtraction

Answer 4

if you multiply both sides by \(a^2\) you get
\[\huge 1-a=6a^2\] and now you have a quadratic equation to solve

Answer 5

if you do the subtraction first you get \[\frac{1-a}{a^2}=6\] then multiply both sides by \(a^2\) and you still get \[1-a=a^2\] so i guess it makes no difference
solve \[6a^2+a-1=0\] for \(a\)